[rt-users] "No object mapping for field" when referencing the UserObject of a MembersObject...

[Ruslan Zakirov]

There is example in:
http://wiki.bestpractical.com/view/CodeSnippets

On Thu, May 21, 2009 at 10:11 PM, Ruslan Zakirov
<ruslan.zakirov at gmail.com> wrote:
> As group may have another group as meber as well as user, so records
> in GroupMembers and CachedGroupMembers objects reference Principals.
>
> If you are looking for users only that are members of a group then
> it's easier to do the following:
>
> my $group = ...
> $group->Load...
>
> my $users = $group->UserMembersObj;
> while ( my $user = $users->Next ) {
>   ...
> }
>
> On Thu, May 21, 2009 at 9:46 PM, Johnathan Bell
> <johnathan.bell at baker.edu> wrote:
>> Please let me know if this is supposed to go to RT-Users or RT-Devel.
>>
>> I'm trying to write a utility to interface with Request Tracker, and
>> part of what that utility has to do is get the members of some user
>> created groups. Just sub in actual groups for what you want in there,
>> CurrentUser works and is already initialized by the time my program gets
>> here. Mostly borrowing this code from the old rtimportldap script, I
>> came up with this:
>>
>> --code--
>>    # RT Group
>>    $groupObj = new RT::Group($CurrentUser);
>>    $groupObj->LoadUserDefinedGroup($groupName);
>>    $groupObj->Id() || die "Group ".$groupName." not found in
>> RequestTracker";
>>
>>    $groupMembersObj = $groupObj->MembersObj();
>>    print $groupObj->Id().":".$groupObj.":".$groupMembersObj.":"
>>        .$groupMembersObj->Next()->UserObj()."\n"; ## This creates an error
>>    while ( $groupMember = $groupMembersObj->Next() )
>>    {
>>        $groupMemberUser = $groupMember->UserObj();
>>        print $groupMemberUser->Name()."\n"; ## This does too
>>        #$memberName = $groupMemberUser->Name();
>>        #push(@rtMembers, $memberName);
>>    }
>> --/code--
>>
>> What it seems is that GroupObj->MembersObj()->Next()->UserObj() causes
>> the problem, as UserObj() returns, not a UserObject, but a string
>> stating "No object mapping for field" Attempting to use the Name()
>> function of course doesn't work because "No object..."->Name() doesn't
>> make sense... What's going on?
>>
>> Thanks,
>> Johnathan
>>
>> --
>> Johnathan Bell
>> Internet System Administrator, Baker College
>>
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>
>
>
> --
> Best regards, Ruslan.
>



-- 
Best regards, Ruslan.