[rt-users] Can't remove incorrect "new ticket" queue entry in dropdown
Kevin Freels
kfreels at sendmail.com
Tue Aug 26 18:28:34 EDT 2008
Okay, still stuck...
I spoke with Jim Meyer (of the LDAP Auth fame) who mentioned that he
thought there was an RTx module called something like
"RTx::who's-reporting" or such. It's designed to do better logging to
find out where stuff is config'd (like my mysterious "default" queue).
Does this sound familiar to anyone?
Again, thanks for all the help!!!!
....k
-=-=-=-
> -----Original Message-----
> From: rt-users-bounces at lists.bestpractical.com
> [mailto:rt-users-bounces at lists.bestpractical.com] On Behalf
> Of Kevin Freels
> Sent: Tuesday, August 05, 2008 2:36 PM
> To: rt Users
> Subject: Re: [rt-users] Can't remove incorrect "new ticket"
> queue entryindropdown
>
> Still stuck on this.... :-(
>
> The affected user(s)(yes, there are more than one) all seem
> now to have the ENG Queue in the "New Ticket" dropdown. I
> have all but removed the user I was originally debugging this
> for (the HR Director); pretty much, she is a privledged user
> and is a member of the HR Group, but the Group has no rights
> and she has no User rights.
>
> If you have the "Quick Search" set up on the "RT at a Glance"
> while logged in as the HR Director user and click on the Edit
> tab for RTaaG, you are presented with the choices of queues
> you'd like to see for QS.
> That Queue ("ENG") is *always* available as a choice. I
> noticed that if I take away the SeeQueue rights for Privedged
> Users in that Queue, the HR Queue disappears from that "RT at
> a glance" Edit option, but not the ENG Queue.
>
> So it looks like the ENG queue is somehow embedded somewhere.
> Is there a way to fix this short of "shredding" it? This is
> affecting more than just this user now, and is becoming a
> show-stopper. Unfortunately, the ENG queue is already in
> production, so it would be extremely difficult for me to
> start over or even upgrade to 3.8.
>
> Thanks for *any* suggestions anyone might have!
>
> ....k
> -=-=-=-
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