[rt-users] setting a 'default cc' on a queue, and letting userschange their own passwords...
Marouane Himdi
marouane.himdi at kereval.com
Wed Oct 25 04:46:10 EDT 2006
Hi Lee
What Kenneth suggested to you is the best way to do that, but you can also
try this scrip.
------- cleanup code -------------
my $Actor = "support at company.com";
my ($success, $msg)= $self->TicketObj->AddWatcher(
Type => "Requestor",
Email => $Actor);
if (! $success) {
$RT::Logger->info($msg);
return undef;
}
return 1;
---------------------------------------------
Best regards
Marouane
-----Message d'origine-----
De : rt-users-bounces at lists.bestpractical.com
[mailto:rt-users-bounces at lists.bestpractical.com] De la part de Kenneth
Crocker
Envoyé : lundi 23 octobre 2006 20:56
À : Lee Whalen
Cc : rt-users at lists.bestpractical.com
Objet : Re: [rt-users] setting a 'default cc' on a queue, and letting
userschange their own passwords...
Lee,
Have you tried creating a group with the required address and then
making that group a "cc" watcher for a Queue? Then you could just create
a notification scrip for "cc". As to you second question, have you tried
"ModifySelf" as a global right for "Privileged" users?
Kenn
LBNL
Lee Whalen wrote:
> Greetings everyone, thank you all for your invaluable help so far.
> I've got just a couple final questions, then I promse I'll STFU for
> awhile and lurk on the list to see if I can help out others. My latest
> questions with RT are: is it possible to set up a default/automatically
> applied CC address for new tickets? It'd be great if whenever a person
> created a ticket that the email "support at somecompany.com" would be
> automagically added to the requestors.
>
> Second question: is there a permission I can grant on individual users
> (or even entire groups) that would allow the individual users to change
> their own passwords? I thought it was ModifyOwnMembership on the custom
> group they belong to ("Users" in this case), but it appears that I'm
> mistaken. Has anyone else been able to set this up?
>
> Many thanks!
> --Lee
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